[Roorkee 1995]
A) $ \log 2/e $
B) $ \log 4 $
C) $ \log 4/e $
D) $ \log 2 $
Correct Answer: C
$ \int_1^{2}{\log xdx=[x\log x-x]_1^{2}=2\log 2-2+1} $
$ =\log 4-1=\log 4-\log e=\log \frac{4}{e} $ .
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