Definite Integration Question 444
Question: The area bounded by the curve $ y^{2}(2-x)=x^{3} $ and x = 2 is
Options:
A) $ 1/\sqrt{3} $
B) ½
C) 1
D) 1/3
Show Answer
Answer:
Correct Answer: A
Solution:
[a] The area bounded by $ y^{3}=4ax $ and $ x^{2}=4by $ is $ \frac{16ab}{3}. $
Then the area bounded by $ y^{2}=x/a $ and $ x^{2}=y/a $ is $ \frac{1}{3a^{2}}. $
Given $ \frac{1}{3a^{2}}=1\Rightarrow a=\pm \frac{1}{\sqrt{3}}. $
BETA
