Definite Integration Question 481
Question: Area under the curve $ y=x^{2}-4x $ within the x-axis and the line $ x=2 $ , is
[SCRA 1991]
Options:
A) $ \frac{16}{3}sq.unit $
B) $ -\frac{16}{3}sq.unit $
C) $ \frac{4}{7}sq.unit $
D) Cannot be calculated
Show Answer
Answer:
Correct Answer: A
Solution:
$ \int_0^{2}{(x^{2}-4x)dx=[ \frac{x^{3}}{3}-\frac{4x^{2}}{2} ]_0^{2}=\frac{16}{3}sq.} $ unit.
BETA
