Definite Integration Question 490
Question: If $ I=\int_0^{\pi /4}{{{\sin }^{2}}xdx} $ and $ J=\int_0^{\pi /4}{{{\cos }^{2}}xdx,} $ then $ I= $
[SCRA 1989]
Options:
A) $ \frac{\pi }{4}-J $
B) $ 2J $
C) $ J $
D) $ \frac{J}{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
Adding $ I+J=\int_0^{\pi /4}{dx=\frac{\pi }{4}\Rightarrow I=\frac{\pi }{4}-J} $ .
BETA
