Definite Integration Question 6
Question: The function $ F(x)=\int_0^{x}{\log ( \frac{1-x}{1+x} )}dx $ is
Options:
A) A function is even if f(-x) = f(x) for all x in its domain.
B) A function is odd if f(-x) = -f(x) for all x in its domain.
C) A periodic function is a function that repeats its values in regular intervals or periods.
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
We know that if $ f(t) $ is an odd function, then $ \int_0^{x}{f(t)} $ dt is an even function. since the function here $ f(x)=\log \frac{1-x}{1+x} $ is an odd function, therefore $ F(x) $ is an even function.
BETA
