Definite Integration Question 60
Question: Area bounded by the parabola $ y=4x^{2}, $
$ y- $ axis and the lines $ y=1,y=4 $ is
[MNR 1990]
Options:
A) 3 sq. unit
B) $ \frac{7}{5} $ sq. unit
C) $ \frac{7}{3} $ sq. unit
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
Required area = $ \int_1^{4}{xdy=\int_1^{4}{\frac{\sqrt{y}}{2}dy}} $
= $ \frac{1}{2}.\frac{2}{3}|{y^{3/2}}|_1^{4}=\frac{7}{3} $ sq. unit.
BETA
