Definite Integration Question 61
Question: The area bounded by the curve $ y=4x-x^{2} $ and the $ x- $ axis, is
[MP PET 1999, 2003]
Options:
A) $ \frac{30}{7} $ sq. unit
B) $ \frac{31}{7} $ sq. unit
C) $ \frac{32}{3} $ sq. unit
D) $ \frac{34}{3} $ sq. unit
Show Answer
Answer:
Correct Answer: C
Solution:
We have $ y=4x-x^{2} $ and $ y=0 $ ; $ \therefore $ $ x=0 $ , $ 4 $
Required area $ =\int_0^{4}{(4x-x^{2})dx=[ \frac{4x^{2}}{2}-\frac{x^{3}}{3} ]_0^{4}} $
$ =32-\frac{64}{3}=\frac{32}{3} $ sq. unit.
BETA
