Definite Integration Question 66
Question: $ \int_1^{2}{e^{x}( \frac{1}{x}-\frac{1}{x^{2}} )dx=} $
[MNR 1990; AMU 1999; UPSEAT 2000; Pb. CET 2004]
Options:
A) $ \frac{e^{2}}{2}+e $
B) $ e-\frac{e^{2}}{2} $
C) $ \frac{e^{2}}{2}-e $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ \int_1^{2}{e^{x}( \frac{1}{x}-\frac{1}{x^{2}} )dx=[ \frac{1}{x}e^{x} ]_1^{2}=\frac{e^{2}}{2}-e} $ .