Definite Integration Question 66

Question: $ \int_1^{2}{e^{x}( \frac{1}{x}-\frac{1}{x^{2}} )dx=} $

[MNR 1990; AMU 1999; UPSEAT 2000; Pb. CET 2004]

Options:

A) $ \frac{e^{2}}{2}+e $

B) $ e-\frac{e^{2}}{2} $

C) $ \frac{e^{2}}{2}-e $

D) None of these

Show Answer

Answer:

Correct Answer: C

Solution:

$ \int_1^{2}{e^{x}( \frac{1}{x}-\frac{1}{x^{2}} )dx=[ \frac{1}{x}e^{x} ]_1^{2}=\frac{e^{2}}{2}-e} $ .