[Karnataka CET 2003]
A) 0
B) 4
C) 8
D) 1
Correct Answer: B
$ \int_0^{\pi }{2\sin xdx+\int _{\pi }^{2\pi }{0.dx}} $
$ =2[-\cos x]_0^{\pi }+0 $
$ =-2(\cos \pi -\cos 0) $
$ =-2(-1-1)=4 $ .
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