Definite Integration Question 80
Question: Area under the curve $ y=\sqrt{3x+4} $ between $ x=0 $ and $ x=4, $ is
[AI CBSE 1979, 80]
Options:
A) $ \frac{56}{9} $ sq. unit
B) $ \frac{64}{9} $ sq. unit
C) 8 sq. unit
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
Area $ =\int_0^{4}{\sqrt{3x+4}}dx=| \frac{{{(3x+4)}^{3/2}}}{3.(3/2)} |_0^{4} $
$ =\frac{2}{9}\times 56=\frac{112}{9}sq. $ unit.
BETA
