Definite Integration Question 97
Question: The value of integral $ \int_0^{1}{{e^{x^{2}}}}dx $ lies in interval
[CEE 1993]
Options:
A) $ (0,1) $
B) ( $ -1,0) $
C) $ (1,e) $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
For $ 0<x<1 $ , we have $ 1<{e^{x^{2}}}<e $ ,
so that $ \int_0^{1}{1dx<\int_0^{1}{{e^{x^{2}}}}dx<\int_0^{1}{edx}\Rightarrow 1<\int_0^{1}{{e^{x^{2}}}dx<e.}} $
BETA
