Definite Integration Question 98
Question: If $ P=\int_0^{3\pi }{f({{\cos }^{2}}x)dx}andQ=\int_0^{\pi }{f({{\cos }^{2}}x)dx} $ , then
[Orissa JEE 2004]
Options:
A) $ P-Q=0 $
B) $ P-2Q=0 $
C) $ P-3Q=0 $
D) $ P-5Q=0 $
Show Answer
Answer:
Correct Answer: C
Solution:
$ P=\int_0^{3\pi }{f({{\cos }^{2}}x)dx} $ and $ Q=\int_0^{\pi }{f({{\cos }^{2}}x)dx} $
Also, $ P=3\int_0^{\pi }{f({{\cos }^{2}}x)dx=3Q} $
therefore $ P-3Q=0 $ .
BETA
