Determinants Matrices Question 28
Question: The number of values of k for which the system of equations $ (k+1)x+8y=4k; $
$ kx+(k+3)y=3k-1 $ has infinitely many solutions is
Options:
A) 0
B) 1
C) 2
D) infinite
Show Answer
Answer:
Correct Answer: B
Solution:
- [b] For infinitely many solutions the two equations become identical
$ \Rightarrow \frac{k+1}{k}=\frac{8}{k+3}=\frac{4k}{3k-1}\Rightarrow k=1 $
BETA
