Differential Equations Question 187
Question: If m and n are the order and degree of the differential equation $ {{( \frac{d^{2}y}{dx^{2}} )}^{5}}+4\frac{{{( \frac{d^{2}y}{dx^{2}} )}^{3}}}{( \frac{d^{3}y}{dx^{3}} )}+\frac{d^{3}y}{dx^{3}}=x^{2}-1 $ , then
[Karnataka CET 1999]
Options:
A) m = 3 and n = 5
B) m = 3 and n = 1
C) m = 3 and n = 3
D) m = 3 and n = 2
Show Answer
Answer:
Correct Answer: D
Solution:
The highest order $ (m) $ of the given equation is $ \frac{d^{3}y}{dx^{3}}=3 $ and degree $ (n) $ of the given equation is $ {{( \frac{d^{3}y}{dx^{3}} )}^{2}}=2 $ . Therefore $ m=3 $ and $ n=2 $ .
BETA
