Differential Equations Question 191
Question: The degree of the differential equation $ 3\frac{d^{2}y}{dx^{2}}={{{ 1+{{( \frac{dy}{dx} )}^{2}} }}^{3/2}} $ is
[MP PET 1994, 95]
Options:
A) 1
B) 2
C) 3
D) 6
Show Answer
Answer:
Correct Answer: B
Solution:
$ 3\frac{d^{2}y}{dx^{2}}={{{ 1+{{( \frac{dy}{dx} )}^{2}} }}^{3/2}} $
On squaring, we get $ 9{{( \frac{d^{2}y}{dx^{2}} )}^{2}}={{{ 1+{{( \frac{dy}{dx} )}^{2}} }}^{3}} $
Obviously the highest derivative $ \frac{d^{2}y}{dx^{2}} $ contains a degree 2.
BETA
