Differential Equations Question 216
Question: The order and degree of the differential equation $ \rho =\frac{{{[ 1+{{( \frac{dy}{dx} )}^{2}} ]}^{3/2}}}{d^{2}y/dx^{2}} $ are respectively
[MP PET 2001; UPSEAT 2002]
Options:
A) 2, 2
B) 2, 3
C) 2, 1
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ \rho .\frac{d^{2}y}{dx^{2}}={{[ 1+{{( \frac{dy}{dx} )}^{2}} ]}^{3/2}} $
Therefore $ {{( \rho .\frac{d^{2}y}{dx^{2}} )}^{2}}={{[ 1+{{( \frac{dy}{dx} )}^{2}} ]}^{3}} $
order = 2, degree = 2.
BETA
