Differential Equations Question 226
Question: The degree of the differential equation $ {{( 1+{{( \frac{dy}{dx} )}^{2}} )}^{3/4}}={{( \frac{d^{2}y}{dx^{2}} )}^{1/3}} $ is
[Karnataka CET 2004]
Options:
A) $ \frac{1}{3} $
B) 4
C) 9
D) $ \frac{3}{4} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ {{[ 1+{{( \frac{dy}{dx} )}^{2}} ]}^{3/4}}={{( \frac{d^{2}y}{dx^{2}} )}^{1/3}} $
Therefore $ {{[ 1+{{( \frac{dy}{dx} )}^{2}} ]}^{9}}={{( \frac{d^{2}y}{dx^{2}} )}^{4}} $
Clearly, degree is 4.
BETA
