Differential Equations Question 23
Question: The solution of $ {e^{2x-3y}}dx+{e^{2y-3x}}dy=0 $ is
Options:
A) $ e^{5x}+e^{5y}=c $
B) $ e^{5x}-e^{5y}=c $
C) $ {e^{5x+5y}}=c $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ {e^{2x-3y}}dx+{e^{2y-3x}}dy=0 $
Multiply the equation by $ {e^{3x+3y}} $
Therefore $ e^{5x}dx+e^{5y}dy=0 $
On integrating, we get $ e^{5x}+e^{5y}=5c’=c $ .
BETA
