Differential Equations Question 280
Question: What is the degree of the differential equation $ k\frac{d^{2}y}{dx^{2}}={{[ 1+{{( \frac{dy}{dx} )}^{3}} ]}^{3/2}} $ , where k is a constant-
Options:
A) 1
B) 2
C) 3
D) 4
Show Answer
Answer:
Correct Answer: B
Solution:
[b] In the given equation, $ K.\frac{d^{2}y}{dx^{2}}={{[ 1+{{( \frac{dy}{dx} )}^{3}} ]}^{3/2}} $
Squaring both the sides, $ K^{2}.{{( \frac{d^{2}y}{dx^{2}} )}^{2}}={{[ 1+{{( \frac{dy}{dx} )}^{3}} ]}^{3}} $
Degree of a differential equation is the highest power of the highest derivative in equation when derivatives are expressed as polynomial. Here degree of differential equation is 2.
BETA
