[MP PET 1999]
A) $ x $
B) $ \log x $
C) $ -x $
D) $ e^{x} $
Correct Answer: A
I.F. $ ={e^{\int _{{}}^{{}}{p.dx}}} $
Therefore $ {e^{\int _{{}}^{{}}{\frac{1}{x}dx}}}={e^{{\log _{e}}x}}=x $ .
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