Differential Equations Question 319
Question: The solution of the differential equation $ \frac{dy}{dx}+\frac{1+x^{2}}{x}=0 $ is
Options:
A) $ y=-\frac{1}{2}{{\tan }^{-1}}x+c $
B) $ y+\log x+\frac{x^{2}}{2}+c=0 $
C) $ y=\frac{1}{2}{{\tan }^{-1}}x+c $
D) $ y-\log x-\frac{x^{2}}{2}=c $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{dy}{dx}+\frac{1+x^{2}}{x}=0 $
Therefore $ dy+( \frac{1}{x}+x )dx=0 $
On integrating, we get $ y+\log x+\frac{x^{2}}{2}+c=0 $ .
BETA
