Differential Equations Question 332
Question: The solution of $ \frac{dy}{dx}=x\log x $ is
[MP PET 2003]
Options:
A) $ y=x^{2}\log x-\frac{x^{2}}{2}+c $
B) $ y=\frac{x^{2}}{2}\log x-x^{2}+c $
C) $ y=\frac{1}{2}x^{2}+\frac{1}{2}x^{2}\log x+c $
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{dy}{dx}=x\log x $
Therefore $ dy=x\log xdx $
Therefore $ \int _{{}}^{{}}{dy=}\int _{{}}^{{}}{x\log xdx} $
Therefore $ y(0)=0 $ .
BETA
