Differential Equations Question 354
Question: The solution of the equation $ \frac{dy}{dx}=y(e^{x}+1) $ is
[AISSE 1986; AI CBSE 1984]
Options:
A) $ y+{e^{(e^{x}+x+c)}}=0 $
B) $ \log y=e^{x}+x+c $
C) $ \log y+e^{x}=x+c $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{dy}{dx}=y(e^{x}+1) $
Therefore $ \frac{dy}{y}=(e^{x}+1)dx $
Integrating both sides, we get $ \log y=e^{x}+x+c $ .
BETA
