Differential Equations Question 53
Question: The differential equation of all circles in the first quadrant which touch the coordinate axes is of order
Options:
A) 1
B) 2
C) 3
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
The equation of the family of circle which touch both the axes is $ {{(x-a)}^{2}}+{{(y-a)}^{2}}=a^{2}, $ where a is a parameter. This is one parameter family of curves. So its differential equation is of order one.
BETA
