Differential Equations Question 69
Question: The solution of the equation $ (2y-1)dx-(2x+3)dy=0 $ is
[Kerala (Engg.) 2002]
Options:
A) $ \frac{2x-1}{2y+3}=c $
B) $ \frac{2y+1}{2x-3}=c $
C) $ \frac{2x+3}{2y-1}=c $
D) s $ \frac{2x-1}{2y-1}=c $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{dy}{2y-1}=\frac{dx}{2x+3} $
Therefore $ \frac{1}{2}\log (2y-1)=\frac{1}{2}\log (2x+3)+\log c $
Therefore $ \frac{2x+3}{2y-1}=c $ .
BETA
