Differential Equations Question 89
Question: The degree of the differential equation $ ( \frac{2+\sin x}{1+y} )\frac{dy}{dx}=-\cos ,x\ y(0)=1, $ is
[Pb. CET 2003]
Options:
A) 1
B) 2
C) 3
D) 6
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{d^{2}y}{dx^{2}}=-\sqrt{1+{{( \frac{dy}{dx} )}^{3}}} $
On squaring, we get $ {{( \frac{d^{2}y}{dx^{2}} )}^{2}}=1+{{( \frac{dy}{dx} )}^{3}} $
Obviously the degree is 2.
BETA
