Differentiation Question 165
Question: If $ y=\sin [\cos (\sin x)], $ then $ dy/dx= $
Options:
A) $ -\cos [\cos (\sin x)]\sin (\cos x).\cos x $
B) $ -\cos [\cos (\sin x)]\sin (\sin x).\cos x $
C) $ \cos [\cos (\sin x)]\sin (\cos x).\cos x $
D) $ \cos [\cos (\sin x)]\sin (\sin x).\cos x $
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Answer:
Correct Answer: B
Solution:
$ y=\sin {\cos (\sin x)} $
Therefore $ \frac{dy}{dx}=-\cos {\cos (\sin x)}\sin (\sin x)\cos x $ .