Differentiation Question 165

Question: If $ y=\sin [\cos (\sin x)], $ then $ dy/dx= $

Options:

A) $ -\cos [\cos (\sin x)]\sin (\cos x).\cos x $

B) $ -\cos [\cos (\sin x)]\sin (\sin x).\cos x $

C) $ \cos [\cos (\sin x)]\sin (\cos x).\cos x $

D) $ \cos [\cos (\sin x)]\sin (\sin x).\cos x $

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Answer:

Correct Answer: B

Solution:

$ y=\sin {\cos (\sin x)} $

Therefore $ \frac{dy}{dx}=-\cos {\cos (\sin x)}\sin (\sin x)\cos x $ .