[RPET 1997]
A) sec x
B) sin x
C) tan x
D) cosec x
Correct Answer: A
$ \frac{d}{dx}{{\cosh }^{-1}}(\sec x) $
$ =\frac{1}{\sqrt{{{\sec }^{2}}x-1}}\frac{d}{dx}\sec x $
$ =\frac{1}{\tan x}.\sec x.\tan x=\sec x $ .
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