[MP PET 1996; Pb. CET 2001]
A) e
B) 1
C) 0
D) $ {\log _{e}}x{e^{{\log _{e}}ex}} $
Correct Answer: A
$ y={e^{1+{\log _{e}}x}}=e^{1}.{e^{{\log _{e}}x}}=e.x\Rightarrow \frac{dy}{dx}=e $ .
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