Differentiation Question 208
Question: If $ y={t^{4/3}}-3{t^{-2/3}} $ , then $ dy/dt $ =
Options:
A) $ \frac{2t^{2}+3}{3{t^{5/3}}} $
B) $ \frac{2t^{2}+3}{{t^{5/3}}} $
C) $ \frac{2(2t^{2}+3)}{{t^{5/3}}} $
D) $ \frac{2(2t^{2}+3)}{3{t^{5/3}}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ y={t^{4/3}}-3{t^{-2/3}} $
$ \therefore \frac{dy}{dt}=\frac{4}{3}{t^{1/3}}+3\times \frac{2}{3}{t^{-5/3}}=\frac{4t^{2}+6}{3{t^{5/3}}}=\frac{2(2t^{2}+3)}{3{t^{5/3}}} $ .
BETA
