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Correct Answer: C
Here $ f’(x)=m $
Therefore $ f’(0)=m=1 $ and $ f(0)=c=1 $. Therefore $ \therefore \frac{dy}{dx}=\frac{3}{2}{{(x{{\cot }^{3}}x)}^{1/2}}[{{\cot }^{3}}x+3x{{\cot }^{2}}x(-cose{c^{2}}x)] $ .
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