A) 1
B) 2
C) 3
D) - 3
Correct Answer: C
Here $ f’(x)=m=1 $
Therefore $ f’(0)=m=1 $ and $ f(0)=c=1 $ . Therefore
$ \therefore \frac{dy}{dx}=\frac{3}{2}{{(x{{\cot }^{3}}x)}^{1/2}}[{{\cot }^{3}}x+3x{{\cot }^{2}}x(-cose{c^{2}}x)] $ .
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