Differentiation Question 217
Question: $ \frac{d}{dx}( \frac{\log x}{\sin x} )= $
Options:
A) $ \frac{\frac{\sin x}{x}-\log x.\cos x}{\sin x} $
B) $ \frac{\frac{\sin x}{x}-\log x.\cos x}{{{\sin }^{2}}x} $
C) $ \frac{\sin x-\log x.\cos x}{{{\sin }^{2}}x} $
D) $ \frac{\frac{\sin x}{x}-\log x}{{{\sin }^{2}}x} $
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Answer:
Correct Answer: B
Solution:
$ \frac{d}{dx}( \frac{\log x}{\sin x} )=\frac{\frac{\sin x}{x}-\log x.\cos x}{{{\sin }^{2}}x} $ .
BETA
