[DSSE 1979]
A) $ \sin (\sin x^{2}).\cos x^{2}.2x $
B) $ -\sin (\sin x^{2}).\cos x^{2}.2x $
C) $ -\sin (\sin x^{2}).{{\cos }^{2}}x.2x $
D) None of these
Correct Answer: B
$ \frac{d}{dx}{\cos (\sin x^{2})}=-\sin (\sin x^{2})\cos x^{2}.2x $ .
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