Differentiation Question 243
Question: $ \frac{d}{dx}[ {{\tan }^{-1}}\sqrt{\frac{1-\cos x}{1+\cos x}} ]= $
[BIT Ranchi 1989; Roorkee 1989; RPET 1996]
Options:
A) $ -\frac{1}{2} $
B) 0
C) $ \frac{1}{2} $
D) 1
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{d}{dx}[ {{\tan }^{-1}}\sqrt{\frac{1-\cos x}{1+\cos x}} ]=\frac{d}{dx}[ {{\tan }^{-1}}\tan \frac{x}{2} ]=\frac{1}{2} $ .
BETA
