A) $ {{(z-a)}^{2}} $
B) $ -{{(z-a)}^{2}} $
C) $ {{(z+a)}^{2}} $
D) $ -{{(z+a)}^{2}} $
Correct Answer: A
Here $ z=a-\frac{1}{y} $
Therefore $ \frac{dz}{dy}=\frac{1}{y^{2}}={{(a-z)}^{2}} $
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