Differentiation Question 262
Question: The derivative of $ {{\sin }^{2}}x $ with respect to $ {{\cos }^{2}}x $ is
[DCE 2002]
Options:
A) $ {{\tan }^{2}}x $
B) $ \tan x $
C) $ -\tan x $
D) None of these
Show Answer
Answer:
Correct Answer: D
Solution:
Let $ y={{\sin }^{2}}x $ and $ z={{\cos }^{2}}x $
Therefore $ \frac{dy}{dx}=\sin 2x $ and $ \frac{dz}{dx}=-\sin 2x $ , \ $ \frac{dy}{dz}=-1 $ .
BETA
