Differentiation Question 266
Question: If $ y=x\sin x, $ then
Options:
A) $ \frac{1}{y}\frac{dy}{dx}=\frac{1}{x}+\cot x $
B) $ \frac{dy}{dx}=\frac{1}{x}+\cot x $
C) $ \frac{1}{y}\frac{dy}{dx}=\frac{1}{x}-\cot x $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ y=x\sin x $
Therefore $ \frac{dy}{dx}=x\cos x+\sin x $
Therefore $ \frac{1}{y}\frac{dy}{dx}=\cot x+\frac{1}{x} $ .
BETA
