Differentiation Question 269
Question: If $ f(x)=(x-x_0)g(x) $ , where $ g(x) $ is continuous at $ x_0 $ , then $ f’(x_0) $ is equal to
Options:
A) 0
B) $ x_0 $
C) $ g(x_0) $
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ f’(x_0)=\underset{x\to x_0}{\mathop{\lim }}\frac{(x-x_0)g(x)-0}{x-x_0}=\underset{x\to x_0}{\mathop{\lim }}g(x)=g(x_0) $
Since g is continuous.
BETA
