Differentiation Question 272
Question: $ \frac{d}{dx}[ \frac{2}{\pi }\sin x^{0} ]= $
Options:
A) $ \frac{\pi }{180}\cos x^{0} $
B) $ \frac{1}{90}\cos x^{0} $
C) $ \frac{\pi }{90}\cos x^{0} $
D) $ \frac{2}{90}\cos x^{0} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{d}{dx}[ \frac{2}{\pi }\sin x{}^\circ ]=\frac{d}{dx}[ \frac{2}{\pi }\sin \frac{\pi .x}{180} ] $
$ =\frac{2}{\pi }\frac{\pi }{180}\cos \frac{x\pi }{180}=\frac{\cos x{}^\circ }{90} $ .
BETA
