Differentiation Question 276
Question: At $ x=\sqrt{\frac{\pi }{2}},\frac{d}{dx}\cos (\sin x^{2}) $ =
Options:
A) -1
B) 1
C) 0
D) None of these
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{d}{dx}[\cos (\sin x^{2})]=-\sin (\sin x^{2})\cos x^{2}.2x $
Putting $ x=\sqrt{\frac{\pi }{2}}, $ we have $ =-2\sqrt{\frac{\pi }{2}}\sin ( \sin \frac{\pi }{2} )\cos \frac{\pi }{2}=0 $ , $ [ \because \cos \frac{\pi }{2}=0 ] $ .
BETA
