Differentiation Question 277
Question: $ \frac{d}{dx}[{{\tan }^{-1}}(\cot x)+{{\cot }^{-1}}(\tan x)]= $
Options:
A) 0
B) 1
C) - 1
D) - 2
Show Answer
Answer:
Correct Answer: D
Solution:
$ \frac{d}{dx}[{{\tan }^{-1}}(\cot x)+{{\cot }^{-1}}(\tan x)] $
= $ \frac{1(-cose{c^{2}}x)}{1+{{\cot }^{2}}x}-\frac{1({{\sec }^{2}}x)}{1+{{\tan }^{2}}x}=-1-1=-2 $ .
BETA
