Differentiation Question 281
Question: If $ y={{\sin }^{-1}}( \frac{19}{20}x )+{{\cos }^{-1}}( \frac{19}{20}x ) $ , then $ \frac{dy}{dx}= $
Options:
A) 0
B) 1
C) - 1
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ y={{\sin }^{-1}}( \frac{19}{20}x )+{{\cos }^{-1}}( \frac{19}{20}x )=\frac{\pi }{2} $
Therefore $ \frac{dy}{dx}=0 $ , $ ( \because {{\sin }^{-1}}x+{{\cos }^{-1}}x=\frac{\pi }{2} ) $ .
BETA
