Differentiation Question 297
Question: If $ y=(1+x^{2}){{\tan }^{-1}}x-x, $ then $ \frac{dy}{dx}= $
[Karnataka CET 2001]
Options:
A) $ {{\tan }^{-1}}x $
B) $ 2x{{\tan }^{-1}}x $
C) $ 2x{{\tan }^{-1}}x-1 $
D) $ \frac{2x}{{{\tan }^{-1}}x} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ y=(1+x^{2}){{\tan }^{-1}}x-x $
Therefore $ \frac{dy}{dx}=(1+x^{2}).\frac{1}{(1+x^{2})}+{{\tan }^{-1}}x(2x)-1=2x{{\tan }^{-1}}x. $
BETA
