Differentiation Question 320
Question: If $ y={{\cot }^{-1}}(x^{2}) $ , then $ \frac{dy}{dx} $ is equal to
[Pb. CET 2002]
Options:
A) $ \frac{2x}{1+x^{4}} $
B) $ \frac{2x}{\sqrt{1+4x}} $
C) $ \frac{-2x}{1+x^{4}} $
D) $ \frac{-2x}{\sqrt{1+x^{2}}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ y={{\cot }^{-1}}( x^{2} ) $
$ \frac{dy}{dx}=\frac{-1}{1+{{(x^{2})}^{2}}}\frac{d}{dx}(x^{2})=\frac{-1}{1+x^{4}}(2x)=\frac{-2x}{1+x^{4}} $ .
BETA
