Differentiation Question 321
Question: If $ y=\log \tan \sqrt{x} $ then the value of $ \frac{dy}{dx} $ is
[Pb. CET 2000]
Options:
A) $ \frac{1}{2\sqrt{x}} $
B) $ \frac{{{\sec }^{2}}\sqrt{x}}{\sqrt{x}\tan x} $
C) $ 2{{\sec }^{2}}\sqrt{x} $
D) $ \frac{{{\sec }^{2}}\sqrt{x}}{2\sqrt{x}\tan \sqrt{x}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ y=\log \tan \sqrt{x} $
$ \frac{dy}{dx}=\frac{1}{\tan \sqrt{x}}.{{\sec }^{2}}\sqrt{x}.\frac{1}{2\sqrt{x}}=\frac{{{\sec }^{2}}\sqrt{x}}{2\sqrt{x}\tan \sqrt{x}} $ .
BETA
