Differentiation Question 346
Question: If $ f(x)=3{e^{x^{2}}} $ ,then $ f’(x)-2xf(x)+\frac{1}{3}f(0)-f’(0)= $
Options:
A) 0
B) 1
C) $ \frac{7}{3}{e^{x^{2}}} $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
We have $ f(x)=3{e^{x^{2}}}. $ Differentiating w.r.t. x, we get $ f’(x)=6x{e^{x^{2}}} $ ;
$ \therefore f(0)=3 $ and $ f’(0)=0 $
Therefore $ f’(x)-2xf(x)+\frac{1}{3}f(0)-f’(0) $
$ =6x{e^{x^{2}}}-6x{e^{x^{2}}}+\frac{1}{3}(3)-0=1 $ .
BETA
