A) $ (n+1)!x $
B) $ (n+1)! $
C) $ n!x $
D) $ n! $
Correct Answer: A
Let $ y={x^{n+1}}; $ then $ y_1=(n+1)x^{n} $
$ y_2=n(n+1){x^{n-1}} $
$ y_3=n(n+1)(n-1){x^{n-2}} $
………………………………. …………………………….. $ y _{n}=(n+1)!x $ .
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