Differentiation Question 367
Question: If $ y={{\sin }^{-1}}\sqrt{x} $ , then $ \frac{dy}{dx}= $
[MP PET 1995]
Options:
A) $ \frac{2}{\sqrt{x}\sqrt{1-x}} $
B) $ \frac{-2}{\sqrt{x}\sqrt{1-x}} $
C) $ \frac{1}{2\sqrt{x}\sqrt{1-x}} $
D) $ \frac{1}{\sqrt{1-x}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ \frac{dy}{dx}=\frac{1}{\sqrt{1-x}}.\frac{d}{dx}(\sqrt{x})=\frac{1}{2\sqrt{x}.\sqrt{1-x}} $ .
BETA
