Differentiation Question 384
Question: If $ y=ae^{x}+b{e^{-x}}+c $ where $ a,b,c $ are parameters then $ {{y}’’}’= $
[EAMCET 2002]
Options:
A) $ y $
B) $ y’ $
C) 0
D) $ y’’ $
Show Answer
Answer:
Correct Answer: B
Solution:
$ y=ae^{x}+b{e^{-x}}+c $
Therefore $ {y}’=ae^{x}-b{e^{-x}} $
Therefore $ {{y}’}’=ae^{x}+b{e^{-x}} $
Therefore $ {{{y}’}’}’=ae^{x}-b{e^{-x}}={y}’ $ .
BETA
