Differentiation Question 390
Question: $ \frac{d}{dx}{{( \sqrt{x}+\frac{1}{\sqrt{x}} )}^{2}}= $
[AI CBSE 1980]
Options:
A) $ 1-\frac{1}{x^{2}} $
B) $ 1+\frac{1}{x^{2}} $
C) $ 1-\frac{1}{2x} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{d}{dx}{{( \sqrt{x}+\frac{1}{\sqrt{x}} )}^{2}}=\frac{d}{dx}[ x+\frac{1}{x}+1 ]=1-\frac{1}{x^{2}} $ .
BETA
